Homework 4	ELET 280		William Crenshaw

4.4
	a. 50,000/2400=I1 = 20.84A	50,000/240=I2 = 208.4A
	b. V1/V2=N1/N2=I2/I1
		2400/240=N1/50	N1=500 turns
	c. (V1/(N1*2*3.1415*f))*sqrt(2) = 0.018 Wb


4.7
	a. N1/N2=I2/I1=V1/V2	Zl'=(N1/N2)^2*(ZL)	V1=6	Zl'=4000 ohms	Zl=100 ohms
		4000=(N1/N2)^2*(100)	N1/N2 = 6.32 turns
	b.	I1=V1/(Zl+Zl') = 6/(4000+4000) = 0.75mA
		I1*(N1/N2)=I2 = 0.75mA=I2/(2*sqrt(10)) = 0.00474 A
		I2*100=V2 = 3/(2*sqrt(10)) = 0.474V
		V2^2/Zl = 2.25 mW

4.16
	theda = cos^-1(Poc/(Voc*Ioc))
	Im = Ioc*sin(theda)
	Iw = Ioc*cos(theda)
	Xm=Voc/Im
	Rc=Voc/Iw
	
	R12=Wsc/(Isc^2)
	Z12=Vsc/Isc
	X12=sqrt(Z12^2-R12^2)

	theda = cos^-1(Poc/(Voc*Ioc)) = 68.28 degrees
	Im=0.2083*sin(theda)=0.1935A	Xm=2400/Im = j12402.31 ohms
	Iw=0.2083*cos(theda)=0.0771A	Rc=2400/Iw = 31135.14 ohms

	R12=615/(20.8333^2) = 1.417 ohms
	Z12=52/20.8333=2.496 ohms
	X12=sqrt(2.496^2-1.417^2) = j2.055 ohms