Homework 5 ELET 280 William Crenshaw 4.31 a. V2=VlL=240<0V N1/N2=10 I2=(50000VA/240V)<-cos^-1(0.9)=208.3334<-25.8419 degrees A I1=I2*(N1/N2)=2083.3334<-25.8419 degrees A Vin=I1*(0.021888+j0.09101)+2400=2528.1860<3.4188 degrees V VNL=Vin/(N1/N2)=252.8186<3.4188 degrees V ((252.8186-240)/240)*100 = 3.34% b. VNLu= (V2+Req*I2*cos(theda)+Xeq*I2*sin(theda)) where a=N1/N2=10 240+0.021888*208.3334*cos(-cos^1(0.9))+0.09191j*208.3334*sin(-cos^-1(0.9)) =244.1042 Unity power factor = ((244.1042-240)/240)*100 = 1.71% c. V2=VlL=240<0V N1/N2=10 I2=(50000VA/240V)